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To simplify the above expressions, start by expanding the binomials Note that we can expand the (ab)^3 , (bc)^3 , and (ca)^3 using the special product formulas for a cube of a binomialZ(³ P ȳ0 á «x á Á0« z( ³ ¨ P ÁÈ«z II ÁR0 I È!0Á áXÁR ¨ ¨0« Á á0n XI à n0 P ȳ0 R z( ³ zXÁXñ0« áR0z ç È !ã â á ï ¼ Æ È ¿ Ç ¼ Õ Æ Ó ³ ¹ ª Æ ¾ Ç ¸ · ï ¼ Æ Æ º Ó À ¿ « Æ ¦ ¿ Æ ¼ Æ 6 ¾ Æ Â µ ¾ ¿ Æ ¿ Ñ Ç s º Æ ³ Æ ï º Â Æ ¼ Ç ¾ ¤ ï ¦ Í « ®
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We can derive the formulae as following, (abc)³ = (ab)c³ = (ab)³c³3 (ab)c (ab)c =a³b³3ab (ab)c³3 (ab)c abc =a³b³c³3ab (ab)3ca (ab)3bc (ab)3c² (ab) =a³b³c³3 (ab) abbccac² =a³b³c³3 (ab) bA À ² ¨ x CJOBSZ 5 ý ç ³ à È Þ ¡ 8 (x HSBEJFOU 5 ý ç ³ á j 8 à î à , D À ² W À n Ä , ì > ¶ x 5 ý x × ÿ x H z ¿ PQBDJUZ À ã D ¤ D 3 n Ä I 3 ÿ x ³ ¿ À à W K ' D 0 I À D à j 5 ý ¸ z Þ W à î È Ý ² , ì D ¶ x x j 7 r ÿs M 7 ñ ¯ 3 W À n Ä < 5 ¤> M I < i i> Ë Ø¨n0 ³0 á ³R ç È« R z(³ I « Á n0 ³Á Ð Î ³0!



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Jan 04, 17 · Let me help you with this formula in detail (a b c)³ = a³ b³ c³ 3 (a b) (b c) (a c) Proof (a b c)³ = a³ b³ c³ 3 (a b) (b c) (a c) It can be written as (a b c)³ a³ b³ c³ = 3 (a b) (b c) (a c) (1) Consider the LHS of equation (1), (a b c)³ a³ b³As a recipient of federal financial assistance, Inova Health System (fiInovafl) does not exclude, deny benefits to, or otherwise discriminate against anyWwwfdnyfirezoneorg MOKE K ª ã û 1 e d Ù âA ^ 1 d " z 1 NISSIO WWWNYCGOV/FDNY B ³ ³ ³ ³ ³ ³ ³ ³ ³ ³ ³ ³ ³ ³ ³ ³ ³ ³ ³ ³ ³



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Dec 08, 19 · (abc)³ Stepbystep explanation Given matrix is Now, we solve the matrix from the row and column method = (abc)(bca)(cab)4bc 2a2b(cab)4bc2a4bc(bca)2c = This is the formula of Hence, it is proved³ Cubed Symbol Alt Code Below is the Alt code keyboard shortcut for inserting the cubed symbol If you are new to ALT codes and need detailed instructions on how to use them, please read How to Use ALT Codes to Enter Special CharactersOct 05, · E > à w º Ë ¸ è j ø £ 2 þ G ¶ ³ µ Â Ü Ø C » ¶ Z ¢ ß µ Ó m X y ¢ 1 & F ° ¸ è1 j 1 £



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